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x^2+2x=14.5924
We move all terms to the left:
x^2+2x-(14.5924)=0
We add all the numbers together, and all the variables
x^2+2x-14.5924=0
a = 1; b = 2; c = -14.5924;
Δ = b2-4ac
Δ = 22-4·1·(-14.5924)
Δ = 62.3696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{62.3696}}{2*1}=\frac{-2-\sqrt{62.3696}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{62.3696}}{2*1}=\frac{-2+\sqrt{62.3696}}{2} $
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